in reply to looping idiom

This method is not guaranteed to work if your array contains references:
foreach (@data) { print; print "\t" if \$_ != \$data[-1]; }

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Jeff[japhy]Pinyan: Perl, regex, and perl hacker, who'd like a (from-home) job
s++=END;++y(;-P)}y js++=;shajsj<++y(p-q)}?print:??;