in reply to Re: codeperl -pe 's/\n/
in thread codeperl -pe 's/\n/" " . /e' data/code
My understanding of the situation is that the regular expression operator iterates over the entire string before it moves on to the "implicit" print. This makes the order
If it did the print as step three, surely you would end up with
one two
three four
Update nuance hangs his head in shame :-( I really will have to learn to read posts properly, of course the original node mentions joining pairs of lines. Doh!
As you can all see, my understanding was wrong.
Nuance
Baldrick, you wouldn't see a subtle plan if it painted itself purple and danced naked on top of a harpsichord, singing "Subtle plans are here again!"
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
RE: RE: Re: codeperl -pe 's/\n/
by ZZamboni (Curate) on May 26, 2000 at 19:59 UTC |