in reply to ORDER BY COUNT(*)?

The problem might be that you need a column-name for "ordering":
SELECT DISTINCT surveys, COUNT(*) AS x FROM neverland GROUP BY surveys + ORDER BY x
Maybe, with mysql the following might work also:
SELECT DISTINCT surveys, COUNT(*) FROM neverland GROUP BY surveys ORDE +R BY 2

Best regards,
perl -le "s==*F=e=>y~\*martinF~stronat~=>s~[^\w]~~g=>chop,print"