in reply to ORDER BY COUNT(*)?
Maybe, with mysql the following might work also:SELECT DISTINCT surveys, COUNT(*) AS x FROM neverland GROUP BY surveys + ORDER BY x
SELECT DISTINCT surveys, COUNT(*) FROM neverland GROUP BY surveys ORDE +R BY 2
Best regards,
perl -le "s==*F=e=>y~\*martinF~stronat~=>s~[^\w]~~g=>chop,print"
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