Yes it does, but if you just stick $ref; out there by itself, or with () after it, perl doesn't get that that's supposed to be a function call and throws a syntax error.
You pretty much have to have the & as far as I know.
Or you could use $ref->(); It's monday and I'm being a blonde.
Update:Thanks chromatic, Fletch, and shotgunefx for the clue-by-four-ing.
/\/\averick
perl -l -e "eval pack('h*','072796e6470272f2c5f2c5166756279636b672');"
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Unless I want the behavior, I usually call a code ref with
$ref->();
Probably 9 out of 10 times you can get away with it but it can product subtle bugs. I wasn't originally aware of the implied passing of @_ and it was never a problem.. until.
-Lee
"To be civilized is to deny one's nature."
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