split "\n", $line;

--
Casey

How about split '\n', $line;

That's still splitting on a pattern, not a literal. Quotes are only special to split in those cases described in perlfunc, otherwise they are regex delimiters.

The same holds true for the rhs of a '=~' expression.

chh@scallop chh> perl -le '$a="foo\nbar"; print $1 if $a =~ "\n(.*)"'
bar
chh@scallop chh>
[download]

It's potentially misleading but not wrong.

It's obsolete, in there for backward compatibility.. go read USENET, you'll see what I mean.

--
Casey