in reply to Re: Re: Pipe, fork, exec and red-hot pokers.
in thread Pipe, fork, exec and red-hot pokers.
Then you will find that no output is captured by read. The perl program must set $|=1, which is exactly what I don't want to have to worry about.#!/usr/bin/perl my $i=0; while (1) { print "stdout " . $i++ . "\n"; sleep 1; }
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