in reply to Open to suggestions on a search and replace..

$line =~ s/^(R.*\$SUB=)<\*\d+>/$1/;

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Re: Re: Open to suggestions on a search and replace..
by tachyon (Chancellor) on Apr 12, 2002 at 11:05 UTC

    You can use a positive lookahead assertion to avoid having to reinsert $1.

    $line =~ s/^(?=R.*\$SUB=)<\*\d+>//;

    cheers

    tachyon

    s&&rsenoyhcatreve&&&s&n.+t&"$'$`$\"$\&"&ee&&y&srve&&d&&print

      You can use a positive lookahead assertion to avoid having to reinsert $1. $line =~ s/^(?=R.*\$SUB=)<\*\d+>//;

      aehhm, this won't work. The lookahead doesn't move the position in your regex, so you are effectively looking for /^<\*\d+>/ which isn't there. Instead you would need a look behind assertion but they are only available for constant length.

      As I understand the file format there are no other digits in angle brackets starting with a star. So why not simply write: s/<\*\d+>//;

      Update: As of Rhodium's clarification of the specs, I would now fully recommend IO's solution.

      -- Hofmator

        Hey Hof,
        As I understand the file format there are no other digits in angle brackets starting with a star.
        That is something I don't want to assume..
        Rhodium

        The <it>seeker</it> of perl wisdom.