Thats interesting - I was under the impression brackets were used as a memory more than a precedence operator... do they provide precedence in the conventional sense of the word and therefore why does this not work...

... to look for all the occurences of an equals sign that is not got whitespace on either side?

Thanks.

I have yet to see your code where that regex "does not work". It works for me.

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Jeff[japhy]Pinyan: Perl, regex, and perl hacker, who'd like a (from-home) job
s++=END;++y(;-P)}y js++=;shajsj<++y(p-q)}?print:??;