Chomp Anomaly?

arunhorne has asked for the wisdom of the Perl Monks concerning the following question:

Hi, i say chomp($data); where data contains a string, in return I get 00 or 01 10 or some other binary rather than a string with no \n's etc. Can anyone shed some light.

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Re: Chomp Anomaly? by ariels (Curate) on May 09, 2002 at 12:08 UTC
chomp modifies its arguments, but returns the number of characters removed from its arguments. What you mean by "some other binary" is unclear; in any case, as per documentation, `print chomp($x = "A string\n"),"\n"; print "\|$x\|\n"` [download] prints 1 \|A string\|	[reply] [d/l]
Re: Chomp Anomaly? by broquaint (Abbot) on May 09, 2002 at 12:09 UTC
This is because `chomp()` modifies the arguments it is passed, so `$/` is removed inplace (which would be `\n` in your case). The return you're seeing is the total number of characters removed from all it's arguments (perhaps you're calling it in an iterative context?). HTH `_________ broquaint`	[reply]