#!/usr/bin/perl -naF/,/
$seen{$F[3]}->{$F[4]}++ if defined $F[3] and defined $F[4];
END { while(($k,$v) = each %seen) { print "$k has accessed $k2 $v2 tim
+es.\n" while ($k2,$v2) = each %$v } }
[download]

^_^

Update: The folks in the chatterbox made me itchy. Golfing time anyone? (Mostly I just didn't want to be beaten out by use of the propositions I mentioned in CB myself.. ^_^)

#!/usr/bin/perl -naF/,/
$seen{"@F[4,3]"}++;END{@u;print"@u has accessed $s $t times.\n"while($
+_,$t)=each%seen,($s,@u)=split}
[download]

____________
Makeshifts last the longest.