in reply to (OT) Hofstadter Metapuzzle

If we are counting numbers and not digits: s/_/1/g; s/(1s is)  1/${1} 10/;

Makeshifts last the longest.

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(MeowChow) Re2: (OT) Metapuzzle
by MeowChow (Vicar) on May 23, 2002 at 05:13 UTC
    Sorry, we're counting digits. Otherwise the puzzle wouldn't be one :) 
       MeowChow                                   
               s aamecha.s a..a\u$&owag.print
[reply]
      Drop one "number of X is" and it still would be. :-)
      ____________
      Makeshifts last the longest.
[reply]
        I'll take X = 1, thankyouverymuch. 
           MeowChow                                   
               s aamecha.s a..a\u$&owag.print
[reply]

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