or vs || precedence issue

my $y = int rand 10 or die; This will work correctly since or binds losely. 10 is regarded as a parameter to rand which is regarded as a parameter to int; the result will be tested with or and die 1 out of 10 times. my $y = int rand 10 || die; This will never die since || binds tightly and causes 10 || die to be evaluated first. The result of that expression is then passed to rand as a parameter, and so on.

Sometimes, very rarely, you actually want the tight binding rather than the lose, however.

Makeshifts last the longest.

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Re: or vs precedence issue by emilford (Friar) on Jun 09, 2002 at 15:31 UTC
Cool! I was quite unaware of the difference between \|\| and or. If it makes that much of a difference, I'll start using or in place of \|\| when checking return errors. Thanks for the reply, the information was very useful.	[reply]
Re^2: or vs precedence issue by Aristotle (Chancellor) on Jun 09, 2002 at 20:03 UTC
Nononono. Not everywhere. Everywhere it belongs. Neither one is "the right one". Please take the time to understand exactly why they each work the way they do. Here's a hint: everything you can do with the one, you can also do with the other, as long as parens regulate precedence. Makeshifts last the longest.	[reply]