perldoc -f unshift
       unshift ARRAY,LIST
               Does the opposite of a "shift".  Or the opposite
               of a "push", depending on how you look at it.
               Prepends list to the front of the array, and
               returns the new number of elements in the array.

                   unshift(ARGV, '-e') unless $ARGV[0] =~ /^-/;

               Note the LIST is prepended whole, not one element
               at a time, so the prepended elements stay in the
               same order.  Use "reverse" to do the reverse.
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OUCH, can't believe I made that mistake...I am done for the night...I meant shift....I am trying to walk the array and remove some value that meet a certain criteria. I just switched to using a temp array to save the "good" ones...

If I walk them backwards, can I pop them off while enumerating ???

thanks

Now that you've explained what you want to do...

Take a look at splice. shift and pop remove values from the ends of an array, not the current position.

From perlsyn section "Foreach Loops":


If any part of LIST is an array, foreach will get very confused if you add or remove elements within the loop body, for example with splice. So don't do that.

As merlyn and tadman imply below, the "right" way to do it depends on what else you are doing in that chunk of code, and on your future use of @list (both pre- and post-modification).