Re: post-increment/pre-increment blues

print ++$i + 1;          # prints 2, increment and than add 1
print $i++ + 1;          # prints 2, $i==1, take the old $i (1) and ad
+d 1, the increment happens after the sum was calculated  
print $i + $i++;         # prints 5, $i==2, the increments happens fir
+st and we get 2+3
print ++$i + ++$i;       # prints 10, $i==3, the pre increment is done
+ twice because it's precedens on '+' and than we get 5+5
print ++$i + $i++ + 1;   # prints 14, $i==5, didn't figure out yet
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Thanks.

Hotshot

Comment on Re: post-increment/pre-increment blues Download Code

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Re: Re: post-increment/pre-increment blues by hotshot (Prior) on Jun 18, 2002 at 09:56 UTC
I see by the answer of fatvamp that we got different ansewr I guess ariels answer is the right one Thanks. Hotshot	[reply]
Re: Re: post-increment/pre-increment blues by Juerd (Abbot) on Jun 18, 2002 at 14:59 UTC
print $i + $i++; # prints 5, $i==2, the increments happens first and we get 2+3 3 + 2, not 2 + 3. Not that it matters, of course. - Yes, I reinvent wheels. - Spam: Visit eurotraQ.	[reply]