in reply to oldschool math
Here is my try. It adds numbers, but is not limited to two arguments. It's recursive and probably not very efficient. (Anyone want to benchmark the two solutions?)
Proof that it works:sub add { my $current = 0; return '' unless @_ = grep length, @_; $current += substr $_, -1, 1, '' for @_; push @_, substr $current, 0, -1, '' if length $current > 1; return &add . $current; }
$\ = "\n"; print add( '999999999999999999999997', '1', '2' ); print add( '9999999999', '9999999999', '999999999', '999', '9' ); # Next line is not -w safe: "Deep recursion"... grin. print add('9' x 5000, 1) eq '1' . ('0' x 5000) ? "Works" : "Doesn't wo +rk";
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Re: Re: oldschool math
by PerpLexicon (Novice) on Jul 02, 2002 at 20:34 UTC |