in reply to Re: Playing with $[
in thread Playing with $[

Okay, I get it now. So I could still do some playing around with
@rray = ( 'foo', 'bar', 'spam', 'eggs' ); $[=3; $calar = $[; print $rray[$calar] while $calar++<@rray;
but not
@rray = ( 'foo', 'bar', 'spam', 'eggs' ); $[=$#rray $calar = $[; print $rray[$calar] while $calar++<@rray;
Good to know. Thanks, jsprat

LAI
:eof