Why won't it work?

Hmmm...

$a = 'foo $\ bar';

print $a =~ /$\/;
print $a.$/;
[download]

One might be quick to assume the output as:

1foo $\ bar
[download]

But a monk would know better...

-Inno

Comment on Why won't it work? Select or Download Code

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SPOILER Re: Why won't it work? by domm (Chaplain) on Jul 11, 2002 at 20:37 UTC
Because the \ after the $ escapes the /, so the regex looks like /$\/;print $a.$/ `-- #!/usr/bin/perl for(ref bless{},just'another'perl'hacker){s-:+-$"-g&&print$_.$/}` [download]	[reply] [d/l]