For a further explanation on this, see perlop under the heading "Comma Operator".

However with regards to the => operator and the quotes, the use of this operator is synonymous with the comma operator which in the scalar context, evaluates the left argument.

But print allways uses list context. So print doesn't get the string 'This::is::it', but a list consisting of  'This::is::it', '', '', which still evaluates to 'This::is::it'

Try this:


perl -we "print test'bla=>$/"
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You'll see that the value of $/ will be printed, as => is just another comma operator, so the above is the same as


perl -we "print test'bla,$/"
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You can pack in even more commas:


perl -we "print test'bla=>=>=>=>=>''"
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(BTW, I've been using the single-quote-as-package-delimiter trick for quite some time in my .sig>

--
#!/usr/bin/perl
for(ref bless{},just'another'perl'hacker){s-:+-$"-g&&print$_.$/}
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