in reply to ($$) and 1;

foo($$); &foo($0);
From perlsub:

Not only does the & form make the argument list optional, it also disables any prototype checking on arguments you do provide. This is partly for historical reasons, and partly for having a convenient way to cheat if you know what you're doing

regards,
tomte

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Re: Re: ($$) and 1;
by Jaap (Curate) on Aug 01, 2002 at 13:32 UTC
    Wow that helps! Thank you. I do find it a rather odd feature though. I always thought it was better to ise the &, turns out it isn't.