Re: removing duplicate letters

This seems to work:

s/(.)\1/$1/g;
[download]

The tr operator does what you want, except it squashes all duplicates, not just two. For reference though:

tr/a-zA-Z//s;
[download]

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RE: Re: removing duplicate letters by Ovid (Cardinal) on Jun 19, 2000 at 00:50 UTC
Actually, the dot operator doesn't fit his definition. eduardo specified letters so we should change it to `s/(\w)(\1)/$1/g;` [download] Update: Oops! takshaka exposed me for the fake I am! (see reply below)	[reply] [d/l]
RE: RE: Re: removing duplicate letters by takshaka (Friar) on Jun 19, 2000 at 01:53 UTC
If we're going to be pedantic, \w matches nonletters as well. Use a character class with the appropriate definition of "letters". `s/([a-zA-Z])\1/$1/g;`	[reply] [d/l]
RE: RE: RE: Re: removing duplicate letters by mdillon (Priest) on Jun 19, 2000 at 05:39 UTC
if you want to talk about pedantic, your letters may not be the letters everyone else is using, so to take the locale into effect, you could do something like the following: `s/([^\W\d_])\1/$1/g`	[reply] [d/l]
RE: Re: removing duplicate letters by eduardo (Curate) on Jun 19, 2000 at 00:01 UTC
damn it ;) that's it, that's what i wanted... `s/(.)\1/$1/g;` [download] oh well, what i kept on trying was: `s/(.)\$1/$1/g;` [download] and that sure as hell didn't work ;) thank you very much!	[reply] [d/l] [select]