spq has asked for the wisdom of the Perl Monks concerning the following question:

I'm developing CGI's and modules for use under Apache with mod_perl. I would _like_ to have a module access the value of a variable in the callers package, namely $DEBUG.

$main::DEBUG works fine in the module when it is run from test.pl (make test). But when called from the CGI, it's undefined. OK, I looked at (caller)[0] (the callers package), which looks like (in my current project:
Apache::ROOTweb_2emgh_2eharvard_2eedu::dnacore::cgi_2dbin::synthesis::CE_QC</p>

So, since it will change, I thought I'd try to use the package name as a symbolic reference(slightly abridged):

my $pkg = (caller)[0]; no strict; warn("${$pkg::DEBUG} in $pkg"); # see what it gets

Which was still undefined. But if I use the package string literally:
warn("$Apache::ROOTweb_2emgh_2eharvard_2eedu::dnacore::cgi_2dbin::synthesis::CE_QC::DEBUG in $pkg");

I get the value expected. I've thrashed around and skimmed the docs for a while now, trying different ways of bracketing, attempting to typeglob, etc. Now it's way past time I ate and I'm frustrated. Please, if anyone can help solve this, I would, as always, be very appriciative!

TIA,
Sean

Replies are listed 'Best First'.
Re: symbolic reference to variable in callers name space
by Fletch (Bishop) on Aug 06, 2002 at 17:11 UTC

    ITYM ${"${pkg}::DEBUG"}.

    ${$pkg::DEBUG} is the variable named by the value contained in the variable $DEBUG in package pkg.

Re: symbolic reference to variable in callers name space
by danboo (Beadle) on Aug 06, 2002 at 18:05 UTC
    for your warn example, i believe you want:
    warn(${"${pkg}::DEBUG"} . " in $pkg"); # see what it gets

    - danboo
      Thank you both! That does indeed work. I did need to change:
      warn("DEBUG = ${"${pkg}::DEBUG"} in $pkg");

      in my code (which threw a syntax error about missing bracket!?), to:
      warn("DEBUG = " . ${"${pkg}::DEBUG"} . " in $pkg");

      Which did the trick for testing. Thanks again! Sean