in reply to Is this a correct way of obtaining input from a file?
Here you're assigning $_ to three different variables before you even read the next value from your file. This means that in each interation of your while loop (i.e. for each value in the file), you assign that line to each variable. Ultimately, the last line of the file gets assigned to all 3 variables, and you're left with the output you received.while (<DATAFILE>) { $TRACK = $_; chomp ($TRACK); $pager = $_; chomp ($pager); $service = $_; chomp ($service); }
What you actually wanted to do was skip the while loop and either do...
...or use DamnDirtyApe's version above, which I prefer. Just keep in mind that each time <DATAFILE> is accessed as a scalar, another line is read from the file, whereas each time $_ is accessed, you're simply retrieving the value of that variable (not the next value in the file).open (DATAFILE, $datafile) or die "Input data not found.\n"; chomp ($TRACK = <DATAFILE>); chomp ($pager = <DATAFILE>); chomp ($service = <DATAFILE>);
-Bird
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Re: Re: Is this a correct way of obtaining input from a file?
by cecil36 (Pilgrim) on Aug 06, 2002 at 21:20 UTC | |
by cecil36 (Pilgrim) on Aug 06, 2002 at 21:28 UTC |