in reply to Array to hash refs

Here is all i could come up with:
use strict; my @a = ('a'..'f'); my $hash; my $last = 1; for (reverse @a) { $hash->{$_} = $last; $last = {$_ => $hash->{$_}}; } delete $hash->{$a[$_]} for (1..@a);
Hehehe, i waited until Abigail-II posted first though. Now i am going to spend some time figuring out how that works ... need more coffee!

UPDATE: Ok, let's figure Abigail-II's code out ...

When dealing with loops, a good way to understand the code is to chart out what happens at each iteration - The key to this code is the atomic triple assignment inside the while loop. Break that into 3 seperate assignments and the results are not the same. Abigail-II++ :)

UPDATE*2:
I think i like Anony's answer the best ... now that is using Perl to write Perl! /smack forehead

jeffa

L-LL-L--L-LL-L--L-LL-L--
-R--R-RR-R--R-RR-R--R-RR
B--B--B--B--B--B--B--B--
H---H---H---H---H---H---
(the triplet paradiddle with high-hat)

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Re: (jeffa) Re: Array to hash refs
by Abigail-II (Bishop) on Aug 14, 2002 at 09:18 UTC
    You can break it into 4 separate assignments though....

    Abigail