in reply to Re: Perl6 - value vs. reference issues
in thread Perl6 - value vs. reference issues

$a = \$b should set $a to be a reference of $b (a reference being an actual separate object), and $a := $b should set $a to be an alias of $b (an alias being only a name reference that is resolved at compile-time). I think thats the case, at least :)


:^) # Fear the wrath of the hyper smiley!