in reply to Insane Uses for Perl

Off-topic, I'm sure... but this line only gives me a compile error: 
perl -le 's ssSss.s sSsSiss.s s$sSss.ss .$s\107ss.print'

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Backslash found where operator expected at -e line 1, near "$s\"
        (Missing operator before \?)
Bareword found where operator expected at -e line 1, near "107ss"
        (Missing operator before ss?)
syntax error at -e line 1, near "$s\"
Execution of -e aborted due to compilation errors.

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What gives...?

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Re: Re: Insane Uses for Perl
by jj808 (Hermit) on Sep 15, 2002 at 14:07 UTC
    I think that Sigmund is trying to use the s character as the delimeter in a substitution. Replacing this with / changes the code from 
    perl -le 's ssSss.s sSsSiss.s s$sSss.ss .$s\107ss.print'

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    to 
    perl -le 's //S/s.s /S/Sis/.s /$/S/s.s/ .$/\107/s.print'

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    This prints 
    SisS

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    Sigmund, is this correct?

    UPDATE:
    I have just read this node: Beware the S ! where Sigmund explains his signature, so it would appear that there was just a typo in the original post.

    The correct version, 

    perl -le 's ssSss.s sSsSiss.s s$sSss.s s.$s\107ss.print'

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    works fine and prints 
    SiG

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    Basically the 16th s should have been after the space, not before it.

    JJ

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