in reply to unique random numbers
Deleting a hash element returns its value, so if you define the %availableNumbers hash like this:
you get to choose and delete at the same time.my ($lidno, $perbin, %lists) = (10, 10); my %availableNumbers = map { $_ => $_ } 1..$lidno*$perbin;
for my $lid (1..$lidno) { my %deck = %availableNumbers; $lists{$lidno} = [ map { delete %deck{ (keys %deck)[rand( keys %deck)]} } 1..$perbin ]; }
That could have been folded into another map, but enough is enough ;-)
After Compline,
Zaxo
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