Re: regex question

You must have mistyped something, try it again please!

If you want to match only the exact words, not longer strings containing them use

   $_ =~ /^$words$/
[download]

The ^ states that the word must be found at the very beginning of the line, $ means the very end.

Jenda

Comment on Re: regex question Download Code

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Re: Re: regex question by zigdon (Deacon) on Sep 24, 2002 at 17:34 UTC
though don't forget that `/^$words$/` [download] expands to `/^word1\|word2\|word3$/` [download] What you probably want to do is `/^(?:$words)$/` [download] -- Dan	[reply] [d/l] [select]
Re: Re: Re: regex question by gnu@perl (Pilgrim) on Sep 24, 2002 at 17:57 UTC
This will shoot in a little different direction, but I was wondering about the '?:'. dosen't that just keep the match from being placed into $_?	[reply]
Re: Re: Re: Re: regex question by zigdon (Deacon) on Sep 24, 2002 at 18:14 UTC
`(?:...)` means that the paren are only used to group, but not to save the match in $1. No real difference, except it's supposed to be faster. See perlre for more info. -- Dan	[reply] [d/l]
Re: Re: regex question by gnu@perl (Pilgrim) on Sep 24, 2002 at 17:37 UTC
DOH! Thanks. I tried that b4 and it didn't work, but I just realized what I had wrong. In my 'playing around' with things I had changed /$words/ to /^$words/ then to /^^$words$/ not thinking that when the $words alternate list is placed inside [] the '\|' is taken literaly and not as a seperator for the alternates. I just put it as /^$words$/ and things seem to be working fine. Thanks for your help and pointing out my 'lil mistke.	[reply]