in reply to Splitting strings with enclosed delimiters

I'd still use a regex to collect the contents of the lines :

use strict;
my $line;
while ($line = <DATA>) {
  chomp $line;
  print $line,"\n";
  while ($line =~ s/(?:^([^" ]+)|^"([^"]+)")(?: |$)//) {
    print ">>>",$1||$2,"\n";
    print $line,"\n";
  };
};
__DATA__
"72 3267S" "S2079" 1 no
"72 0250" "S3011" 1 no
"72 8351S" "S6101" 1 no
"72 17082S" "S6108" 1 no

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The regex nibbles from the start of each line either something starting with a non-quote, or a quote and then everything including the ending quote and the separating space. At the end of a line, no space is allowed.

perl -MHTTP::Daemon -MHTTP::Response -MLWP::Simple -e ' ;    # The  
$d = new HTTP::Daemon and fork and getprint $d->url and exit;#spider
($c = $d->accept())->get_request(); $c->send_response( new   #in the
HTTP::Response(200,$_,$_,qq(Just another Perl hacker\n))); ' #  web

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•Re: Re: Splitting strings with enclosed delimiters
by merlyn (Sage) on Oct 03, 2002 at 18:45 UTC
    Nibbling regex are expensive. Change it to a scalar m/\G.../g walk, and you have a winner: 
    use strict;
my $line;
while ($line = <DATA>) {
  chomp $line;
  print $line,"\n";
  while ($line =~ m/\G(?:([^" ]+)|"([^"]+)")(?: |$)/g) {
    print ">>>",$1||$2,"\n";
    print $line,"\n";
  };
};
__DATA__
"72 3267S" "S2079" 1 no
"72 0250" "S3011" 1 no
"72 8351S" "S6101" 1 no
"72 17082S" "S6108" 1 no

    [download]

    -- Randal L. Schwartz, Perl hacker

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[d/l]

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