how about if you work the problem the other way.
Base 2 Base 10
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.0001 == 0/2 + 0/4 + 0/8 + 1/16 == .0625
.0010 == 0/2 + 0/4 + 1/8 + 0/16 == .125
.0011 == 0/2 + 0/4 + 1/8 + 1/16 == .1875
.0100 == 0/2 + 1/4 + 0/8 + 0/16 == .25
.0101 == 0/2 + 1/4 + 0/8 + 1/16 == .3125
.0110 == 0/2 + 1/4 + 1/8 + 0/16 == .375
.0111 == 0/2 + 1/4 + 1/8 + 1/16 == .4375
.1000 == 1/2 + 0/4 + 0/8 + 0/16 == .5
.1001 == 1/2 + 0/4 + 0/8 + 1/16 == .5625
.1010 == 1/2 + 0/4 + 1/8 + 0/16 == .625
.1011 == 1/2 + 0/4 + 1/8 + 1/16 == .6875
.1100 == 1/2 + 1/4 + 0/8 + 0/16 == .74
.1101 == 1/2 + 1/4 + 0/8 + 1/16 == .8125
.1110 == 1/2 + 1/4 + 1/8 + 0/16 == .875
.1111 == 1/2 + 1/4 + 1/8 + 1/16 == .9375

has you can see there are gaps in between the decimal numbers. The more accurate you want to get the more digits in the base 2 numbers you need. Assuming that you're working with a computer that has 32 bit registers you can only store a finite number so you may not always have enough bits to represent the fraction you want.


jjdraco
learning Perl one statement at a time.