in reply to Counting lines by content

I think the easiest way would be to use a hash - something like this?

Oops - just realised this doesn't handle the case where the 3rd field is a duplicate - in fact it doesn't worry about the 3rd field at all. guha has supplied some modifed code, which I've used to replace my slightly dodgy stuff!

#!perl 
use strict;
use warnings;
use diagnostics;

my ($type, $desc, %fruit);

open (FH, "y") || die "Cannot find file";
while (<FH>) {
    (undef, $type, $desc) = split /:/;
    $fruit{$type}{$desc}++;
}
close FH;

foreach my $type (keys(%fruit)) {
    print "$type : ",scalar keys %{ $fruit{$type} }, "\n";
}

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Re: Re: Counting lines by content
by l2kashe (Deacon) on Oct 09, 2002 at 13:47 UTC
    A hash is the right answer, but I believe that he is looking for a hash of hashes.... 
    #!/usr/bin/perl

open(IN,"/some/file") || die "Cant open file\nReason: $!\n";

while (<IN>) {
   chomp($line = $_);

   ($first,$second) = (split(/:/, $line))[1,2];

   $fruit{$first}{count}++;
   $fruit{$first}{$second}++;
}
close(IN);

foreach $k (sort(keys(%fruit))) {
   print "$k $fruit{$k}{count}\n";
}

    [download]
    The reason I used count as well, is so A) I dont have to loop to figure out what my total count for $first is, and B) I also can test for $fruit{$k}{blah} and determine if there were duplicates. You could add the test within the while loop.. I.e test for $fruit{$first}{$second} and if it exists warn or something, else increment it :)... Have fun /* * And the Creator, against his better judgement, wrote man.c */
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