Re: •Re: If Statement

3. # The syntax would be ambiguous without it. I forget the exact case,...

It's like this:

        if ( $foo )
               if ( $bar )
                     quux();
           else
                # ???
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Which if is that else supposed to go with?

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•Re: Re: •Re: If Statement by merlyn (Sage) on Nov 05, 2002 at 18:18 UTC
No, not the dangling-else problem. I already addressed that in "point 2". There's something that's in Perl that's not in C that would have made it hard to tell if there was a single expression or a block following. Maybe it's just the anonymous hash constructor, but back when braces were made mandatory, there was no anon-hash constructor, so I don't think that was it. -- Randal L. Schwartz, Perl hacker Be sure to read my standard disclaimer if this is a reply.	[reply]

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•Re: Re: •Re: If Statement
by merlyn (Sage) on Nov 05, 2002 at 18:18 UTC

There's something that's in Perl that's not in C that would have made it hard to tell if there was a single expression or a block following. Maybe it's just the anonymous hash constructor, but back when braces were made mandatory, there was no anon-hash constructor, so I don't think that was it.

-- Randal L. Schwartz, Perl hacker
Be sure to read my standard disclaimer if this is a reply.

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