dushu has asked for the wisdom of the Perl Monks concerning the following question:

Hey guys,
Ok, all I want to be able to do is go to a directory on my server, using a cgi script, to search a list of files.
The dir is determined by a form the user fills out. I wat to search the files and then return data. What command will open the dir?
Here is some of my code: 
#!/usr/bin/perl
    
print "Content-type: text/html\n\n"; 
    
require("cgi-lib.cgi");

&ReadParse;

@stuff = "";
$i = 0;
    
foreach $key (keys %in) {
    @stuff[$i] = "$in{$key}";
    $i = $i + 1;
}

chomp @stuff;

$site = @stuff[4];
$year = @stuff[1];
$month = @stuff[5];
$day = @stuff[6];
$star = @stuff[2];
$var = @stuff[0];

$date = $year . $month . $day;
$dir = $site . $date;

#opendir DIR, "/www2/hardwiredsolutions.com/concam/$site/$dir" or die 
+"\nError opening directory";

@filecheck = <*.txt>;

    foreach $file (@filecheck) {
        open FILE, "$file" or die "\nError reading file(1)";
        @lines = <FILE>;
        close FILE;

        open FILE, "$file" or die "\nError reading file(2)";
        foreach $line (@lines) {
            @time = unpack "a26a4a2a*", $line;            
            @words = unpack "a6a7a5a4a4a3a6a6a10a9a10a*", $line;
            s/^\s+// for @time;
            s/^\s+// for @words;
            if (@time[1] eq "GST") {
                chomp @time[3];
                print "@time[3]";
            }
            if (@words[1] eq $star) {
                print "@words[$var+1]<br>";
            }
        }
        
    }

print <<WEB_PAGE;
<html>
<title>Graph the Night Sky!</title><h1>Graph:</h1><hr>
You researched $star, on $date, at $site, for $var.
</html>
WEB_PAGE

[download]
The files I need to access are in a directory like this: kp/kp021020/files_to_search. The dir depends on which file the user enters in the form.
Thanx as always,
Dushu

Replies are listed 'Best First'.
Re: open dir
by emilford (Friar) on Nov 07, 2002 at 17:28 UTC
    First off, you could have done a search for opendir and you would have found exactly what you needed. I didn't look through your code, but if all you want to do is read in the file contents of a directory, you could do something like this: 
    # create a filehandle to the directory - check for errors
opendir (DIR, "path/to/directory") or die "Unable to open directory: $
+!";

# read in all file names except . and ..
@files = grep {$_ ne "." && $_ ne ".."} readdir (DIR);

# close the filehandle to the directory
closedir (DIR);

# do whatever you want with filenames in @files

    [download]
[reply]
[d/l]
Re: open dir
by tachyon (Chancellor) on Nov 07, 2002 at 17:31 UTC 
    # you can do this
$dir = 'c:\\';
opendir DIR, $dir or die "Can't open $dir perl says $!\n";
while ( $file = readdir DIR ) {
    next unless $file =~ m/\.txt$/i;
    print "Found *.txt file: $file\n";
}

# or this
$dir = 'c:\\';
opendir DIR, $dir or die "Can't open $dir perl says $!\n";
my @files = grep { /\.txt$/i } readdir DIR;
print "$_\n" for @files;

# or this
$dir = "c:\\*.txt";
@files = glob $dir;
print "$_\n" for @files;

    [download]

    cheers

    tachyon

    s&&rsenoyhcatreve&&&s&n.+t&"$'$`$\"$\&"&ee&&y&srve&&d&&print

[reply]
[d/l]
Re: open dir
by samurai (Monk) on Nov 07, 2002 at 18:15 UTC
[reply]
Re: open dir
by fglock (Vicar) on Nov 07, 2002 at 17:51 UTC 
    require("cgi-lib.cgi");
&ReadParse;

    [download]

    Change this to  use CGI; if you can. It is safer, and more standards compliant.

[reply]
[d/l]
[select]

Back to Seekers of Perl Wisdom