in reply to Re: New Obfuscation Trick!
in thread New Obfuscation Trick!
But I don't understand the first version. Why does it work? perl 5.8.0 on linux, btw.perl -le ' J}s rule' JAPHs rule perl -le ' $J=q$JAPH$;print"${J}s rule"; ' JAPHs rule
-- Dan
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re: (z) Re^2: New Obfuscation Trick!
by broquaint (Abbot) on Nov 26, 2002 at 18:07 UTC | |
by stefp (Vicar) on Nov 27, 2002 at 05:22 UTC |