Re: Re: chmod and oct

Thanks,

Than my first code was wrong, as it should be:

chmod 0755, $file;
# and not
chmod '0755', $file;
[download]

It is because my variable $chmod is regarded as a string and not a number, that is fails.

Why doesn't a trick like this work then?

$chmod='0644';
chmod $chmod+0, $file;
[download]

Please note that it is friday today, and this might explain my stuped questions :-)

---------------------------
Dr. Mark Ceulemans
Senior Consultant
IT Masters, Belgium

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Re: Re: Re: chmod and oct by dws (Chancellor) on Dec 06, 2002 at 08:55 UTC
Why doesn't a trick like this work then? `$chmod='0644'; chmod $chmod+0, $file;` [download] It doesn't work because "leading zero means octal" applies only to numbers, not strings of numeric digits. Try this: `print 0644, " != ", '0644' + 0, "\n";` This is all described in the on-line doc, in perldata.	[reply] [d/l] [select]