Re: HTTPS Call across proxy server

You already got what you were supposed to get.

You did:

my $request=HTTP::Request->new(POST=> $lstrURL);
[download]

which is a post request, and you got a 200 OK back, which meant that your request had been received, understood and processed by the server.

As you seem to be surprised at this response, and also you said "I do not get the content", I assume what you actually wanted to do was a 'GET' instead of 'POST', then you should do something like:

my $request=HTTP::Request->new(GET => $lstrURL);
[download]

Update: Thanks to jjdraco for pointing out my typo.

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Re: Re: HTTPS Call across proxy server by jjdraco (Scribe) on Dec 13, 2002 at 06:22 UTC
As you seem to be surprised at this response, and also you said "I do not get the content", I assume what you actually wanted to do was a 'GET' instead of 'POST', then you should do something like: `my $request=HTTP::Request->new(POST=> $lstrURL);` [download] I think you meant to say `my $request=HTTP::Request->new(GET=> $lstrURL);` [download] or am I wrong on what I thought I read? jjdraco learning Perl one statement at a time.	[reply] [d/l] [select]
Re: Re: HTTPS Call across proxy server by Anonymous Monk on Dec 13, 2002 at 15:49 UTC
Dear jjdraco, Thanks a lot for the prompt response. I have used `my $request=HTTP::Request->new(GET => $lstrURL);` but the result is the same. I want to get the content between the <HTML></HTML> tags. I am unable to get that. Regards, Binu	[reply] [d/l]