in reply to Re: Perl6: Parting of @Arrayed See
in thread Perl6: Parting of @Arrayed See
What I wonder is whether this can be used to supersede the rather unintuitivemy (@dir, @other); push @{ -d ? \@dir : \@other } for readdir DH;
First of all, I love this perl5 idiom of conditional dereferencing. It is succinct for perl enthusiasts, though probably non-obvious to those new to the language. Hence to your question, can it be more elegant in the part concept described for perl6.
I thought of this as well. For your concept, a simple bang shortcut might suffice (I think this is what you intended, actually):
my(@dir, @other) = part [ -d, ! ] readdir DM;
This was probably what you proposed, sans-typo. The only difference is a '1', which leads me to believe you neglected a shift key (?).
The general case, however, is something I had already considered. It's not merely the negation of a single conditional, it's the leftovers, the default, of the prior conditionals. So we get something like:
(@foo,@bar,@zap,@slop) := part [ /foo/, /bar/, /zap/, ! ] @source;
There's the modified beast. A nice fluffy beast. I like it. (I think basing the 'slop' on a surplus of receiving arrays might be pushing the obfu a bit much)
Matt
P.S. Is it just me, or is this starting to resemble a case statement embedded in a loop?
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Re^3: Perl6: Parting of @Arrayed See
by Aristotle (Chancellor) on Dec 15, 2002 at 12:16 UTC | |
by BrentDax (Hermit) on Jan 10, 2003 at 18:30 UTC |