Re: Syntax Explanation PLs

Running it through B::Deparse reveals that you're close:

perl -MO=Deparse -e '$foo = "blarny!"; print $foo.bar.baz.quux;'
[download]

yields:

$foo = 'blarny!';
print $foo . 'bar' . 'baz' . 'quux';
-e syntax OK
[download]

And prints "blarny!barbazquux".

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Re: Re: Syntax Explanation PLs by submersible_toaster (Chaplain) on Jan 07, 2003 at 07:01 UTC
/me makes mental note to investigate B::Deparse sometime soon. Interestingly enough, and this is now way beyond useful. `$foo = 'hmmm'; bar = 'why?'; print $foo.bar.me` [download] Deparses as `$foo = 'grrr'; do bar = 'why?'; print $foo . 'bar' . 'me';` [download] Of course they break in different ways. `do bar = 'why?'` dies with a compilation error. Can't modify do "file" in scalar assignment `bar = 'why?'` Gets through with a warning, but when used with . results in a error : Undefined subroutine &main::bar. My presumption is 'bar=' does something ugly to the symbol table - and why not? its pretty cruel use of syntax, sadly it's also an easy typo. use strict #or die screaming.$!	[reply] [d/l] [select]

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Re: Re: Syntax Explanation PLs
by submersible_toaster (Chaplain) on Jan 07, 2003 at 07:01 UTC

/me makes mental note to investigate B::Deparse sometime soon. Interestingly enough, and this is now way beyond useful.

$foo = 'hmmm';
bar  = 'why?';
print $foo.bar.me
[download]

$foo = 'grrr';
do bar = 'why?';
print $foo . 'bar' . 'me';
[download]

do bar = 'why?'

bar = 'why?'

use strict #or die screaming.$!