in reply to Re: Re: Re: Re: 0**0
in thread 0**0

lim[x → ∞](x/x) = 1
lim[x → ∞](2x/x) = 2

Now which one do we take?

Makeshifts last the longest.

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Re^6: 0**0
by Arien (Pilgrim) on Jan 19, 2003 at 12:52 UTC

    lim x → ∞ x/x was just an example to show that dividing two numbers that approach infinity is determinate. I didn't mean to suggest that the "division" of infinity by infinity has the value 1 (or 2, or any value for that matter).

    — Arien