Re: Keeping a count of matches in a hash that satisfy more than 1 condition

that sounds like a job for... grep! (now this is untested, but i think i got everything right...)


$menucount = scalar(grep {($file{$_}{FILETYPE} eq "Menu") 
                           && 
                          ($file{$_}{VOICEOVER} eq "No") 
                         } keys %file);
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sound good?

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(jjhorner) Keeping a count of matches in a hash that satisfy more than 1 condition by jjhorner (Hermit) on Jul 19, 2000 at 17:44 UTC
I believe the asker wants to come out of this with 6 new counts, so you would have to use 4 greps, and a couple of subtractions to get all of the counts needed. J. J. Horner Linux, Perl, Apache, Stronghold, Unix jhorner@knoxlug.org http://www.knoxlug.org/	[reply]
RE: (jjhorner) Keeping a count of matches in a hash that satisfy more than 1 condition by eduardo (Curate) on Jul 19, 2000 at 17:49 UTC
very true... i didn't really want to type out all of the greps though! :) the question, as always, now becomes... which is faster, the foreach or the grep! anyone up for a benchmarking of the two? (my guess is the foreach will probably be quicker... but, i would be really curious to see what turns out...)	[reply]