in reply to Re: Re: What is a "stash"?
in thread What is a "stash"?
the ease of using a hash instead of a module that will provide OO representation for you overrides the benefits of not using a hash so.... Yes, right?
How one arrives at such a conclusion is not really important.
I read that "all objects from an array" in one of O'Reilly's advanced perl books too. Having looked at the code required to maintain objects as arrays and the inability to play nicely with serialization tools like Data::Dumper was a real turn off.
Besides, I think the post below referencing the "stash" is probably more correct that anything thus far.
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Re4: What is a "stash"?
by dragonchild (Archbishop) on Feb 06, 2003 at 15:01 UTC |