removing first char of string

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

Replies are listed 'Best First'.
Re: removing first char of string by jacques (Priest) on Feb 10, 2003 at 01:09 UTC
`$string =~ s/^.//s;` This will also work: `substr ($string, 0, 1) = '';`	[reply] [d/l] [select]
Re: removing first char of string by data64 (Chaplain) on Feb 10, 2003 at 00:55 UTC
one way is using the substr function. A related question is answered in Categorized Questions and Answers Just a tongue-tied, twisted, earth-bound misfit. -- Pink Floyd	[reply]
Re: removing first char of string by ihb (Deacon) on Feb 10, 2003 at 01:08 UTC
One popular way is to use a substitution: `s/.//s;` `ihb`	[reply] [d/l] [select]
Re: Re: removing first char of string by Anonymous Monk on Feb 10, 2003 at 01:16 UTC
cool. Thanks so much	[reply]
Re: removing first char of string by jmcnamara (Monsignor) on Feb 10, 2003 at 09:00 UTC
Use substr in the 4 arg form as shown above or in the 2 arg form: `$str = substr $str, 1; # Or in case the string is empty $str = substr $str, 1 if length $str;` [download] -- John.	[reply] [d/l]
Re: removing first char of string by Cabrion (Friar) on Feb 10, 2003 at 02:45 UTC
Or maybe . . `$string = reverse(chop(reverse($string)));` [download] Doh! Thanks ihb. `chop(reverse$string)); $string = reverse($string);` [download] Note to self: Don't offer advice while drinking beer... Sorry all.	[reply] [d/l] [select]
Re: Re: removing first char of string by ihb (Deacon) on Feb 10, 2003 at 03:06 UTC
You didn't actually try that, did you? `:)` It won't work, and that's because `chop()` tries to modify its argument, i.e. it wants an lvalue. The return value of `chop()` returns the (last) removed value, so even if `chop()` could chop the `reverse()`-expression `$string` would hold the first char of itself, and the outer reverse would be useless. `ihb`	[reply] [d/l] [select]