2. I'm using the javascript onSubmit event handler within the form to launch a web-page in another window. I don't think you can call a Perl script with this javascript event handler.

Not that I like js solutions but you can open anyfile in a new window using any handlers, just do:

<form method="post" action="youscript.cgi" onSubmit="open('your_check_
+script.cgi')">
[download]

You can pass some extra parameters to the open function to define how you want it to appear (size scrollbars etc.)

Hope that helps.
Chris

Correction to my previous post to John

You can launch a Perl script from javascript

example:

<SCRIPT LANGUAGE="JavaScript">

function showProgress() {
var newWindow = open("http://localhost/cgi-bin/test.pl", "secondWindow
+", "scrollbars,resizable,width=250,height=150,left=720");
}
</script>
[download]

The form element would contain the following javascript event handler:

onSubmit="showProgress()
[download]

Eoin

This depends on a few things... but, you could have a Perl script that watches the file upload by how much of the file is uploaded so far. You can steal the size of the file from the Content-size: header, pass it to the second script as a query string, and have the script return a page with a meta refresh tag so the page will reload every second or so.

That's putting more strain on the server; how important is it to have a window display the current upload?

John J Reiser
newrisedesigns.com

Thanks John

I actually went down the route you suggested using a little more javascript then you mentioned. Again I ran into the problem that the upload file wasn't actully written out on the server until the entire file had been upload

Obviously the process is storing the chunks of uploaded data in a temp file or cache until everything has been uploaded so my second Perl script has nothing to report on until the file is finally uploaded which, of course, is too late

Just about to give up on this approach and simply have my second Perl script just display a file uploading message and exit when the file has been uploaded

Unless you can access the data as its being uploaded then this approach won't work. Still, I learned a lot of stuff trying it out

Thanks

Eoin