Your code will work, but it exposes a misunderstanding that you have. There is no need to use an array, @temp, to store your array element, $blocks[$blockcount][4], because your array element is a scalar variable. In fact, all array elements are scalars. In your case, that scalar just happens to be a reference to another array.

Your code works because it is simply using the first element of @temp as a temporary variable. This is what you meant to do:

$temp                   = $blocks[$blockcount][4];
$blocks[$blockcount][4] = $blocks[$blockcount][5];
$blocks[$blockcount][5] = $temp;
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And that will be sufficient. You can also use the shorthand that dws suggested to swap values without a temporary variable.

-sauoq
"My two cents aren't worth a dime.";