RE: Array inside hashes

Just a note, \(1, 2, 3) was a good try, but it's actually interpreted as (\1, \2, \3). From perldoc perlref:

Taking a reference to an enumerated list is not the same as using
square brackets--instead it's the same as creating a list of
references!

    @list = (\$a, \@b, \%c);
    @list = \($a, @b, %c);      # same thing!

As a special case, `\(@foo)' returns a list of references to the
contents of `@foo', not a reference to `@foo' itself. Likewise for
`%foo', except that the key references are to copies (since the keys
are just strings rather than full-fledged scalars).
[download]

So, as the previous posters mentioned, the solution is to use [1, 2, 3] instead of \(1, 2, 3).

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RE: RE: Array inside hashes by Anonymous Monk on Jul 22, 2000 at 22:35 UTC
(Offer your reply needs a preview button :) Thanks everyone for their help! I knew I was missing something obvious. athomason mentioned `\($a, @b, %c)` is the same as `(\$a, \@b, \%c)`. But is `\[$a, $b, $c)` the same as `[\$a, \$b, \$c]`? All the array elements are references, so I believe the first method would be cleaner. `$a = "foo"; $b = "bar"; $c = "baz"; @list = \[$a, $b, $c]; foreach(@list) { print $$_ . "\n"; }` [download] Perl appears to set `$list[0]` to a reference to `[$a, $b, $c]`. Is there a less redundant way to say `[\$a, \$b, \$c]`?	[reply] [d/l] [select]
RE: RE: Array inside hashes by Anonymous Monk on Jul 22, 2000 at 22:33 UTC
Thanks everyone for their help! I knew I was missing something obvious. athomason mentioned \($a, @b, %c) is the same as (\$a, \@b, \%c). But is \[$a, $b, $c) the same as \$a, \$b, \$c? All the array elements are references, so I believe the first method would be cleaner. `$a = "foo"; $b = "bar"; $c = "baz"; @list = \[$a, $b, $c]; foreach(@list) { print $$_ . "\n"; }` [download] Perl appears to set $list[0] to a reference to $a, $b, $c. Is there a less redundant way to say \$a, \$b, \$c?	[reply] [d/l]