Re: =~ and substitutions

Hello, This is how to get the code between the tags


 $_ =~ /(<p>)(.*)(<\/p>)/i;
print $2;
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The number $2 picks up the value since it is in the second set of ().
hope this helps

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Re: Re: =~ and substitutions by chromatic (Archbishop) on Mar 03, 2003 at 20:28 UTC
Careful! There are a few gotchas in that snippet. First, there's a greedy match. If you have a string containing `<p>one paragraph</p><p>another paragraph</p>`, `$2` will contain `one paragraph</p><p>another paragraph`. Besides that, if the regex succeeds, `$2` won't contain what you expect. You can also leave off the default variable and certainly don't need to capture the paragraph tags. I'd prefer: `print $1 if m!<p>(.*?)</p>!;` Of course, if there's anything more complicated than bare paragraph tags, you're better off using an HTML parser module.	[reply] [d/l] [select]

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Re: Re: =~ and substitutions
by chromatic (Archbishop) on Mar 03, 2003 at 20:28 UTC

Careful! There are a few gotchas in that snippet. First, there's a greedy match. If you have a string containing one paragraphanother paragraph, $2 will contain one paragraphanother paragraph. Besides that, if the regex succeeds, $2 won't contain what you expect. You can also leave off the default variable and certainly don't need to capture the paragraph tags. I'd prefer:

print $1 if m!(.*?)!;

Of course, if there's anything more complicated than bare paragraph tags, you're better off using an HTML parser module.

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