Re: regex needed

is foo always the second item?

print (split /:/)[1];
[download]

Update: I just noticed that this does not actually run, it spits a syntax error, this, however, works:

print '', (split /:/)[1];
[download]

Anyone can explain this a bit? got anything to do with list|scalar context?

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Comment on Re: regex needed Select or Download Code

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Re:x2 regex needed by grinder (Bishop) on Mar 14, 2003 at 14:44 UTC
Operator precedence and print's hunger for a filehandle get in the way. perl parses that as `(print (split /:/))[1];` [download] And therefore thinks that `(split /:/)` should be a filehandle (not sure about that) and then you're taking a slice of the whole mess (which definitely won't fly). Extra parentheses are all you need. `print( (split /:/)[1] );` [download] print@_{sort keys %_},$/if%_=split//,'= & *a?b:e\f/h^h!j+n,o@o;r$s-t%t#u'	[reply] [d/l] [select]
Re: Re: regex needed by thelenm (Vicar) on Mar 14, 2003 at 17:48 UTC
Another way to keep the parentheses from being grabbed by `print` is to add a + in front of them, like this: `print +(split /:/)[1];` [download] perlfunc explains why this happens: Perl built-in functions can be called with or without parentheses, so when perl sees parentheses there, it associates them with the function call, not with the creation of a list. -- Mike `-- just,my${.02}`	[reply] [d/l] [select]
Re: Re: regex needed by MrYoya (Monk) on Mar 14, 2003 at 19:52 UTC
I believe that the `print (split /:/)[1];` [download] is not working because it first evaluates the `print (split /:/)`, which returns a scalar value, in this case "1" for a successful print. So it's trying to get a list element of a scalar, which does not work. Same as trying `1[0];` .	[reply] [d/l] [select]