Re: Generating characters (0 to 255)

One Unix/Linux boxes, you can man ascii to print a table similar to those found in reference manuals.

Below is something I use to generate an ascii table when I'm not not on a *nix machine and don't have a book. It's pretty much the same as your code, just in the table format.

print "Decimal | Octal | Hex | Character\n";
print "--------+-------+-----+----------\n";

my @hs = (0 .. 9, 'A' .. 'F');
for my $r (@hs) { 
    for my $c (@hs) { 
        my $h = hex($r . $c);
        printf("%-8.8s\| %-6.6s\| %-4.4s\| %-s\n",
                sprintf("%u",     $h),
                sprintf("%-3.3o", $h),
                sprintf("%-2.2X", $h),
                map({ s/\n/\^J/; $_ }
                    sprintf("%c", $h)));
    }   
}
[download]

Update: Removed padding on last column per parv's suggestion below. Great idea!

Comment on Re: Generating characters (0 to 255) Select or Download Code

Replies are listed 'Best First'.
Re: Re: Generating characters (0 to 255) by tachyon (Chancellor) on Mar 28, 2003 at 00:23 UTC
Of course you are going to way too much effort to do this.... `print "Decimal \| Octal \| Hex \| Character\n"; print "--------+-------+-----+----------\n"; printf "%-8s\| %03o \| %02X \|%3s\n",($_)x3,map{$_=/\n/?'^J':/\r/?'^M' +:$_}chr for 1..255;` [download] cheers tachyon s&&rsenoyhcatreve&&&s&n.+t&"$'$`$\"$\&"&ee&&y&srve&&d&&print	[reply] [d/l]
Re^3: Generating characters (0 to 255) by Aristotle (Chancellor) on Mar 30, 2003 at 21:27 UTC
Capture regularities in code, irregularities in data. `my %c = ( map(+(chr,sprintf '\x%02X',$_), 0 .. 31, 127 .. 160), "\a" => '\a', "\b" => '\b', "\e" => '\e', "\f" => '\f', "\n" => '\n', "\r" => '\r', "\t" => '\t', ); print "Decimal \| Octal \| Hex \| Character\n"; print "--------+-------+-----+----------\n"; printf "%7d \| %03o \| %02X \| %4s\n", ($_)x3, $c{+chr}\|\|chr for 1..25 +5;` [download] Makeshifts last the longest.	[reply] [d/l]
Re: Re: Generating characters (0 to 255) by parv (Parson) on Mar 27, 2003 at 21:12 UTC
I must say output of your program is much easier on the the eyes. Since the character is the last item to be printed in your program, number of spaces it takes could be omitted and still get left justified output by using just `printf("%-8.8s\\| %-6.6s\\| %-4.4s\\| %-s\n", ...)`. Otherwise, empty (unoccupied) spaces are printed after each character (which could potentially interfere w/ copy-paste). What do you think?	[reply] [d/l]