#!/usr/bin/perl

use strict;

my %coord_;

$coord_{"AB"}{1} = [420,520,870];
$coord_{"AB"}{2} = [220,520,470];
$coord_{"AB"}{6} = [320,320,270];
$coord_{"AB"}{7} = [520,720,370];
$coord_{"AB"}{8} = [620,520,670];
$coord_{"PL"}{12} = [420,520,570];
$coord_{"PL"}{13} = [220,520,170];
$coord_{"B"}{2} = [320,720,670];
$coord_{"B"}{4} = [520,520,170];
$coord_{"B"}{5} = [620,820,370];

foreach my $key1 (sort keys %coord_)
{
        foreach my $key2 (sort keys %{$coord_{$key1}})
        {
                printf "%s %d = X:%d, Y:%d, Z:%d\n",
                        $key1, $key2, @{$coord_{$key1}{$key2}};
        }

}
[download]

-Matt

The ordering of output isn't quite what you wanted, but that can't be helped with a hash, since it doesn't preserve the order in which you insert the elements.

That is, it could only be helped if you take the trouble to specify a non-canonical order external to the hash, e.g.:

my @key1_order = qw/AB PL B/;
...
foreach my $key1 ( @key1_order ) {
   ...
}
[download]

or assign sortable values within the hash (which could be worked into the hash-creation process):

$coord_{AB}{order} = 1;
$coord_{PL}{order} = 2;
$coord_{B}{order} = 3;
...
foreach my $key1 ( sort { $coord_{$a}{order} <=> $coord_{$b}{order} } 
+keys %coord_ ) {
   ...
}
[download]

The order doesnt matter actually - thanks for your help, your solution worked perfectly.