in reply to to be or not to be...

Wouldn't /^(?:bb)|(?!bb)$/ work better?

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We are the carpenters and bricklayers of the Information Age.

Don't go borrowing trouble. For programmers, this means Worry only about what you need to implement.

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Re: Re: to be or not to be...
by Jenda (Abbot) on Apr 08, 2003 at 15:56 UTC

    Well, not. That would mean "to be at the beginning or not to be at the end". And the /(?!bb)$ would match anything. If you are at the very end of the string you may be sure there are not two more "b"s left. :-)

    Jenda
    Always code as if the guy who ends up maintaining your code will be a violent psychopath who knows where you live.
       -- Rick Osborne

    Edit by castaway: Closed small tag in signature

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