Re: Re: How do I replace certain character if condition exists

This works if you are sure that you won't have any nested parentheses. If you do then it doesn't work at all, for example:

a(b(c))           becomes a b(c))
a (b (c) d (e) f) becomes a  b (c) d (e) f)

Comment on Re: Re: How do I replace certain character if condition exists

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Re: Re: Re: How do I replace certain character if condition exists by kilinrax (Deacon) on Apr 17, 2003 at 16:58 UTC
Well, you can do that with a regex, but it's a good degree more complicated..... `abowley@krait:~$ (echo 'Madrid(Spain(Europe)' && echo 'Madrid(Spain(Eu +rope))' && echo 'Madrid(Spain Europe))' && echo 'a(b(c))' && echo 'a +(b (c) d (e) f)') \| perl -mstrict -wpe 'BEGIN { $brackets = qr#\([^() +](?:(??{$brackets})[^()])*\)# }; s#([^)]+?)($brackets)([^(]+)# ( my + $s = $1 ) =~ tr/(/ /; ( my $e = $3 ) =~ tr/)/ /; $s . $2 . $e #ge;' Madrid Spain(Europe) Madrid(Spain(Europe)) Madrid(Spain Europe) a(b(c)) a (b (c) d (e) f)` [download]	[reply] [d/l]

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Re: Re: Re: How do I replace certain character if condition exists
by kilinrax (Deacon) on Apr 17, 2003 at 16:58 UTC

can

abowley@krait:~$ (echo 'Madrid(Spain(Europe)' && echo 'Madrid(Spain(Eu
+rope))' && echo 'Madrid(Spain Europe))' && echo 'a(b(c))' && echo 'a 
+(b (c) d (e) f)') | perl -mstrict -wpe 'BEGIN { $brackets = qr#\([^()
+]*(?:(??{$brackets})[^()]*)*\)# }; s#([^)]+?)($brackets)([^(]+)# ( my
+ $s = $1 ) =~ tr/(/ /; ( my $e = $3 ) =~ tr/)/ /; $s . $2 . $e #ge;'
Madrid Spain(Europe)
Madrid(Spain(Europe))
Madrid(Spain Europe) 
a(b(c))
a (b (c) d (e) f)
[download]

[reply]
[d/l]